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-6x^2+x+32=0
a = -6; b = 1; c = +32;
Δ = b2-4ac
Δ = 12-4·(-6)·32
Δ = 769
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{769}}{2*-6}=\frac{-1-\sqrt{769}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{769}}{2*-6}=\frac{-1+\sqrt{769}}{-12} $
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